login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A152005
Numbers whose square is the product of two distinct tetrahedral numbers A000292.
1
2, 140, 280, 1092, 166460, 189070, 665840, 804540, 845460, 34250920, 38336088, 133784560, 138535992, 225792840, 4998790160, 6301258040, 7559616818, 8367691640, 39991371446, 104637102152, 227490888350, 1497809326860, 296523233581822
OFFSET
1,1
COMMENTS
There may be values that are not given in the recurrence shown. This sequence is suggested by Ulas, p. 11, who supplied the recurrence.
a(24) > 3*10^14. - Donovan Johnson, Jan 11 2012
FORMULA
a(n) = T(i)*T(j) where T(k) = A000292(k) = C(k+2,3) = k*(k+1)*(k+2)/6.
EXAMPLE
From R. J. Mathar, Jan 22 2009: (Start)
2 is in the sequence because 2^2 = 4*1 = T(2)*T(1).
140 is in the sequence 140^2 = 560*35 = T(14)*T(5) = 19600*1 = T(48)*T(1).
280 is in the sequence because 280^2 = 19600*4 = T(48)*T(2).
1092 is in the sequence because 1092^2 = 3276*364 = T(26)*T(12). (End)
MATHEMATICA
(* This program is not suitable to compute more than a dozen terms. *)
terms = 12; imin = 1; imax = 3000;
Union[Reap[Do[k2 = i(i+1)(i+2)/6 j(j+1)(j+2)/6; k = Sqrt[k2]; If[IntegerQ[k], Print[k]; Sow[k]], {i, imin, imax}, {j, i+1, imax}]][[2, 1]]][[1 ;; terms]] (* Jean-François Alcover, Oct 31 2018 *)
CROSSREFS
Cf. A000292, A175497 (products distinct triangular numbers).
Sequence in context: A265176 A101232 A093887 * A140898 A220513 A120814
KEYWORD
nonn,more
AUTHOR
Jonathan Vos Post, Nov 19 2008
EXTENSIONS
Sequence replaced by sequence with no intermediate terms missing by R. J. Mathar, Jan 22 2009
a(15)-a(18) from Donovan Johnson, Jan 24 2009
a(19)-a(23) from Donovan Johnson, Jan 11 2012
STATUS
approved