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A147579
Numbers with exactly 6 distinct odd prime divisors {3,5,7,11,13,17}.
7
255255, 765765, 1276275, 1786785, 2297295, 2807805, 3318315, 3828825, 4339335, 5360355, 6381375, 6891885, 8423415, 8933925, 9954945, 11486475, 12507495, 13018005, 14039025, 16081065, 16591575, 19144125, 19654635, 20675655, 21696675, 23228205, 25270245, 26801775
OFFSET
1,1
COMMENTS
Numbers k such that phi(k)/k = m
( Family of sequences for successive n odd primes )
m=2/3 numbers with exactly 1 distinct prime divisor {3} see A000244
m=8/15 numbers with exactly 2 distinct prime divisors {3,5} see A033849
m=16/35 numbers with exactly 3 distinct prime divisors {3,5,7} see A147576
m=32/77 numbers with exactly 4 distinct prime divisors {3,5,7,11} see A147577
m=384/1001 numbers with exactly 5 distinct prime divisors {3,5,7,11,13} see A147578
m=6144/17017 numbers with exactly 6 distinct prime divisors {3,5,7,11,13,17} see A147579
m=3072/323323 numbers with exactly 7 distinct prime divisors {3,5,7,11,13,17,19} see A147580
m=110592/323323 numbers with exactly 8 distinct prime divisors {3,5,7,11,13,17,19,23} see A147581
LINKS
FORMULA
Sum_{n>=1} 1/a(n) = 1/92160. - Amiram Eldar, Dec 22 2020
MATHEMATICA
a = {}; Do[If[EulerPhi[255255 x] == 92160 x, AppendTo[a, 255255 x]], {x, 1, 100}]; a
PROG
(Python)
from sympy import integer_log
from oeis_sequences.OEISsequences import bisection
def A147579(n):
ptuple = (3, 5, 7, 11, 13, 17)
def g(x, m): return sum(g(x//(ptuple[m]**i), m-1) for i in range(1, integer_log(x, ptuple[m])[0]+1)) if m else integer_log(x, 3)[0]
return bisection(lambda x: n+x-g(x, 5), 255255*n, 255255*n) # Chai Wah Wu, Mar 18 2026
KEYWORD
nonn
AUTHOR
Artur Jasinski, Nov 07 2008
EXTENSIONS
More terms from Amiram Eldar, Mar 11 2020
STATUS
approved