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A144854
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Values of n such that the expression sqrt(4!*(n+1) + 1) yields a perfect power.
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0
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25, 99, 609, 650, 1189, 3479, 4901, 5429, 11659, 16275, 29469, 38479, 62525, 73814, 78089, 117739, 142449, 201116, 203319, 240199, 328769, 381275, 406900, 504889, 576909, 743775, 839629, 1005731, 1058819, 1183259, 1464709, 1622919, 1960244
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OFFSET
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1,1
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LINKS
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EXAMPLE
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25 is in the sequence since sqrt(4!*(25+1) + 1) = 25 = 5^2;
99 is in the sequence since sqrt(4!*(99+1) + 1) = 49 = 7^2. - Jon E. Schoenfield, Aug 01 2015
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MATHEMATICA
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lst = {}; Do[a = Sqrt[4! (n + 1) + 1]; If[IntegerQ@ a && GCD @@ Last /@ FactorInteger@a > 1, AppendTo[lst, n]], {n, 0, 1977428}]; lst (* Robert G. Wilson v, Sep 24 2008 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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