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A141323
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Number of groups of order L(n).
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2
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1, 1, 1, 2, 1, 1, 5, 1, 1, 4, 1, 1, 4, 2, 1, 9, 1, 1, 30, 1, 1, 11, 5, 1, 4, 1, 2, 9, 2, 1
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OFFSET
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0,4
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COMMENTS
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LINKS
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FORMULA
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EXAMPLE
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a(6) = 5 because the Lucas number L(6) (starting at L(0) = 2) is 18 and there are 5 groups of order 18.
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CROSSREFS
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KEYWORD
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more,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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