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A140987
Number of groups of order F(n).
3
1, 1, 1, 1, 1, 5, 1, 2, 2, 2, 1, 197, 1, 1, 6, 2, 1, 41, 1, 7, 4, 1, 1
OFFSET
1,6
FORMULA
a(n) = A000001(A000045(n)).
EXAMPLE
a(6) = 5 because Fibonacci number F(6) = 8 and there are 5 groups of order 8.
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Jonathan Vos Post, Jul 28 2008
EXTENSIONS
Entries through a(17) checked by N. J. A. Sloane, Aug 01 2008
a(18)-a(23) from Eric M. Schmidt, Jun 19 2014
STATUS
approved