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Number of groups of order L(n).
2

%I #9 Jun 21 2014 04:08:02

%S 1,1,1,2,1,1,5,1,1,4,1,1,4,2,1,9,1,1,30,1,1,11,5,1,4,1,2,9,2,1

%N Number of groups of order L(n).

%C This is to A140987 as Lucas numbers A000032 are to Fibonacci numbers A000045.

%H <a href="http://www.gap-system.org/Packages/grpconst.html">GAP package GrpConst</a>

%F a(n) = A000001(A000032(n)).

%e a(6) = 5 because the Lucas number L(6) (starting at L(0) = 2) is 18 and there are 5 groups of order 18.

%Y Cf. A000001, A000032, A000045, A140987.

%K more,nonn

%O 0,4

%A _Jonathan Vos Post_, Aug 02 2008

%E a(16)-a(29) from _Eric M. Schmidt_, Jun 20 2014