OFFSET
1,1
COMMENTS
The iteration on c = c*log(c)- 1 does not converge from above or below. However, iteration on c = exp(1+1/c) converges quickly from above and below, including negative values. - Richard R. Forberg, Dec 28 2013
c is the solution to the equation 2 = Integral_{t=1...c} log(t) dt. - Colin Linzer, Nov 12 2024
LINKS
G. C. Greubel, Table of n, a(n) for n = 1..5000
Luigi Addario-Berry, Nicolas Broutin and Gabor Lugosi, The longest minimum-weight path in a complete graph, arXiv:0809.0275 [math.CO], 2008-2009.
Steven R. Finch and Li-Yan Zhu, Searching for a Shoreline, arXiv:math/0501123 [math.OC], 2005, p. 10.
Michel Goemans and Jon Kleinberg, An improved approximation ratio for the minimum latency problem, Proc. 7th ACM-SIAM Symposium on Discrete Algorithms, 1996, pp. 152-158.
Henryk Iwaniec, Rosser's sieve, Acta Arithmetica 36:2 (1980), pp. 171-202.
FORMULA
Equals exp(LambertW(1/e)+1).
Equals 1/A202357. - Hugo Pfoertner, Nov 12 2024
EXAMPLE
3.59112147666862213664922292574163484210307540159278691904529873...
MATHEMATICA
RealDigits[ 1 / ProductLog[ 1/E ], 10, 99] // First (* Jean-François Alcover, Mar 07 2013 *)
PROG
(PARI) solve(x=3, 4, x*log(x)-x-1) \\ Charles R Greathouse IV, Feb 22 2016
(PARI) exp(lambertw(exp(-1))+1) \\ Charles R Greathouse IV, Feb 22 2016
CROSSREFS
KEYWORD
nonn,cons
AUTHOR
David Applegate and N. J. A. Sloane, Sep 04 2008
STATUS
approved