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A138235 a(n) = floor(n*(6 + sqrt(6))/5). 7
1, 3, 5, 6, 8, 10, 11, 13, 15, 16, 18, 20, 21, 23, 25, 27, 28, 30, 32, 33, 35, 37, 38, 40, 42, 43, 45, 47, 49, 50, 52, 54, 55, 57, 59, 60, 62, 64, 65, 67, 69, 70, 72, 74, 76, 77, 79, 81, 82, 84, 86, 87, 89, 91, 92, 94, 96, 98, 99, 101, 103, 104, 106, 108, 109, 111, 113, 114 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
Beatty sequence for (6+sqrt(6))/5; complement of A022840;
a(n) = A138236(A022840(n)) and A138236(a(n)) = A022840(n).
Numbers k such that A248515(k+1) = A248515(k) = least number h such that 1 - h*sin(1/h) < 1/n^2. The difference sequence of A248515 is (0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, 0, 1, 0, 1, 0, ...), so that A138235 = (1, 3, 5, 6, 8, ...) and A022840 = (2, 4, 7, 9, 12, 14, ...). - Clark Kimberling, Jun 16 2015
LINKS
Clark Kimberling, Beatty sequences and trigonometric functions, Integers 16 (2016), #A15.
Eric Weisstein's World of Mathematics, Beatty Sequence
MATHEMATICA
With[{c=6+Sqrt[6]}, Table[Floor[(n*c)/5], {n, 80}]] (* Harvey P. Dale, Feb 25 2013 *)
PROG
(Magma) [Floor(n*(6+Sqrt(6))/5): n in [1..70]]; // Vincenzo Librandi, Jun 17 2015
CROSSREFS
Cf. A248515, A022840 (complement).
Sequence in context: A329845 A329993 A064994 * A329833 A059541 A189682
KEYWORD
nonn
AUTHOR
Reinhard Zumkeller, Mar 07 2008
STATUS
approved

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Last modified December 3 18:21 EST 2023. Contains 367540 sequences. (Running on oeis4.)