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A137803
a(n) = floor(n*(sqrt(2) + 1/2)).
18
1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 45, 47, 49, 51, 53, 55, 57, 59, 61, 63, 65, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 89, 91, 93, 95, 97, 99, 101, 103, 105, 107, 109, 111, 112, 114, 116, 118, 120, 122, 124, 126
OFFSET
1,2
COMMENTS
a(n) = A059533(n) for n <= 34;
Beatty sequence for sqrt(2) + 1/2; complement of A137804;
a(n) = A137805(A137804(n)) and A137805(a(n)) = A137804(n).
LINKS
G. C. Greubel, Table of n, a(n) for n = 1..10000 (terms 1..1000 from R. Zumkeller)
Eric Weisstein's World of Mathematics, Beatty Sequence
MATHEMATICA
Floor[Range[80](Sqrt[2]+1/2)] (* Harvey P. Dale, Mar 24 2011 *)
PROG
(PARI) for(n=1, 50, print1(floor(n*(sqrt(2)+1/2)), ", ")) \\ G. C. Greubel, Jan 27 2018
(Magma) [Floor(n*(Sqrt(2)+1/2)): n in [1..50]]; // G. C. Greubel, Jan 27 2018
(Python)
from math import isqrt
def A137803(n): return (n>>1)+(m:=isqrt(r:=n*n<<1))+(n&1)*int(r-m*(m+1)>=1) # Chai Wah Wu, Aug 03 2022
CROSSREFS
Sequence in context: A059547 A064719 A214657 * A059533 A189397 A172100
KEYWORD
nonn
AUTHOR
Reinhard Zumkeller, Feb 11 2008
STATUS
approved