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A137402
a(n) = Sum_{k=0..n} binomial(floor(n-2k/3), k).
3
1, 1, 2, 3, 5, 9, 16, 28, 48, 81, 136, 229, 388, 661, 1129, 1928, 3287, 5594, 9510, 16164, 27484, 46757, 79577, 135454, 230552, 392355, 667620, 1135924, 1932721, 3288563, 5595805, 9522067, 16203273, 27572144, 46917243, 79834375, 135845607, 231154212
OFFSET
0,3
COMMENTS
A_n + B_{n-1} + C_{n-2} in the notation of A137356.
Lim_{n->infinity} a(n+1)/a(n) = x ~= 1.7016..., with x given by the real root (A324498) of (x - 1)^3*x^2 = 1. - Hugo Pfoertner, Mar 15 2019
REFERENCES
D. E. Knuth, The Art of Computer Programming, Vol. 4A, Section 7.1.4.
LINKS
Hùng Việt Chu, Yubo Geng, Julian King, Steven J. Miller, Garrett Tresch, and Zachary Louis Vasseur, Linear Recurrences from Counting Schreier-Type Multisets, Integers 26 (2026), Article A53. See p. 4. See also arXiv:2509.05158 [math.CO], 2025. See p. 4.
FORMULA
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) + a(n-5); a(0)=1, a(1)=1, a(2)=2, a(3)=3, a(4)=5. - Harvey P. Dale, Aug 22 2011
G.f.: (1 - 2*x + 2*x^2 - x^3 + x^4) / (1 - 3*x + 3*x^2 - x^3 - x^5). - Colin Barker, Dec 14 2015
MAPLE
f:=n->add( binomial( floor(n-2*k/3), k), k=0..n);
MATHEMATICA
Table[Sum[Binomial[Floor[n-(2k)/3], k], {k, 0, n}], {n, 0, 40}] (* Harvey P. Dale, Aug 22 2011 *)
(* Alternative: *)
LinearRecurrence[{3, -3, 1, 0, 1}, {1, 1, 2, 3, 5}, 40] (* Harvey P. Dale, Aug 22 2011 *)
PROG
(PARI) Vec((1-2*x+2*x^2-x^3+x^4)/(1-3*x+3*x^2-x^3-x^5) + O(x^50)) \\ Colin Barker, Dec 14 2015
(PARI) a(n) = sum(k=0, n, binomial(floor(n-2*k/3), k)); \\ Altug Alkan, Dec 14 2015
(Magma) [(&+[Binomial(Floor(n-2*k/3), k): k in [0..n]]): n in [0..40]]; // G. C. Greubel, Mar 15 2019
(SageMath) [sum(binomial(floor(n-2*k/3), k) for k in (0..n)) for n in (0..40)] # G. C. Greubel, Mar 15 2019
CROSSREFS
KEYWORD
nonn,easy,changed
AUTHOR
Don Knuth, Apr 11 2008
STATUS
approved