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A135810
Number of coincidence-free length n lists of 4-tuples with all numbers 1,...,n in tuple position k, for k=1..4.
3
1, 0, 15, 1250, 326685, 205713924, 267499350955, 643364455632870, 2637753876195952185, 17316358344270678304520, 173227930768100416550798151, 2536860701329458663625695526890
OFFSET
0,3
COMMENTS
a(n) enumerates (ordered) lists of n 4-tuples such that every number from 1 to n appears once at each of the four tuple positions and the j-th list member is not the tuple (j,j,j,j), for every j=1,..,n. Called coincidence-free 4-tuple lists of length n. See the Charalambides reference for this combinatorial interpretation.
REFERENCES
Ch. A. Charalambides, Enumerative Combinatorics, Chapman & Hall/CRC, Boca Raton, Florida, 2002, p. 187, Exercise 13.(a), for r=4.
LINKS
FORMULA
a(n) = Sum_{j=0,..,n} ( ((-1)^(n-j))*binomial(n,j)*(j!)^4 ). See the Charalambides reference a(n) = B_{n,4}.
EXAMPLE
4-tuple combinatorics: a(1)=0 because the only list of 4-tuples composed of 1 is [(1,1,1,1)] and this is a coincidence for j=1.
4-tuple combinatorics: from the 2^4 possible 4-tuples of numbers 1 and 2 all except (1,1,1,1) appear as first members of the length 2 lists. The second members are the 4-tuples obtained by interchanging 1 and 2. E.g., one of the a(2)=15 lists is [(1,1,1,2),(2,2,2,1)]. The list [(1,1, 1,1),(2,2,2,2) does not qualify because it has in fact two coincidences, those for j=1 and j=2.
MATHEMATICA
Table[Sum[(-1)^k Binomial[n, k](n-k)!^4, {k, 0, n}], {n, 0, 11}] (* Geoffrey Critzer, Jun 17 2013 *)
CROSSREFS
Cf. A135809 (coincidence-free 3-tuples), A135811 (coincidence-free 5-tuples).
Sequence in context: A098723 A120296 A209679 * A273967 A273963 A220179
KEYWORD
nonn,easy
AUTHOR
Wolfdieter Lang, Jan 21 2008, Feb 22 2008
STATUS
approved