|
|
A135172
|
|
a(n) = 3^prime(n) + 2^prime(n).
|
|
1
|
|
|
13, 35, 275, 2315, 179195, 1602515, 129271235, 1162785755, 94151567435, 68630914235795, 617675543767595, 450284043329950835, 36472998576194041955, 328256976190630099835, 26588814499694991643115, 19383245676687219151537715, 14130386092315195257068234555, 127173474827954453552096993555
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Only a(1) = 2^2 + 3^2 = 13 is prime. Since all other primes p are odd, hence of the form 2k+1, we have 2^(2k+1) + 3^(2k+1) is always divisible by 5, and is at best semiprime, such as 3^83 + 2^83 = 3990838394187349600940803592605746684635 = 5 * 798167678837469920188160718521149336927.
a(n) is never a perfect power (A001597), this question was asked during West Germany Olympiad in 1981 (see links). - Bernard Schott, Mar 05 2019
|
|
LINKS
|
|
|
FORMULA
|
|
|
EXAMPLE
|
a(4)=2315 because the 4th prime number is 7, 3^7=2187, 2^7=128 and 2187+128=2315.
|
|
MAPLE
|
|
|
MATHEMATICA
|
|
|
PROG
|
(Python)
from sympy import prime, primerange
def aupton(nn): return [3**p + 2**p for p in primerange(1, prime(nn)+1)]
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|