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A131371
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Number of anagrams of n that are semiprimes.
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4
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0, 0, 0, 1, 0, 1, 0, 0, 1, 1, 0, 1, 0, 1, 2, 0, 0, 0, 1, 0, 1, 1, 0, 0, 1, 2, 0, 1, 0, 0, 0, 0, 1, 1, 1, 0, 0, 1, 2, 0, 1, 0, 1, 0, 0, 1, 1, 0, 2, 0, 2, 1, 1, 0, 1, 1, 1, 2, 1, 0, 0, 2, 0, 1, 1, 0, 0, 1, 1, 0, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 2, 1, 1, 0, 0, 0, 1, 0, 2, 2, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 1
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OFFSET
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1,15
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COMMENTS
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An anagram of a k-digit number is one of the k! permutations of the digits that does not begin with 0.
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LINKS
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EXAMPLE
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a(123) = 3 because 123 = 3 * 41 is semiprime, 213 = 3 * 71 is semiprime, 321 = 3 * 107 is semiprime, while the other anagrams 132, 231 and 312 have respectively 3, 3 and 5 prime factors with multiplicity.
a(129) = 4 because 129 = 3 * 43 is semiprime, 219 = 3 * 73 is semiprime, 291 = 3 * 97 is semiprime, 921 = 3 * 307 is semiprime, while 192 and 912 have 7 and 6 prime factors with multiplicity.
a(134) = 5 because 134 = 2 * 67 and 143 = 11 * 13 and 314 = 2 * 157 and 341 = 11 * 31 and 413 = 7 * 59 are semiprimes, while 431 is prime.
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MAPLE
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f:= proc(n) local L, m, t, i;
L:= convert(n, base, 10); m:= nops(L);
nops(select(t -> t[-1] <> 0 and numtheory:-bigomega(add(t[i]*10^(i-1), i=1..m))=2, combinat:-permute(L)));
end proc:
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PROG
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(Python)
from sympy import factorint
from sympy.utilities.iterables import multiset_permutations as mp
def c(n):
return sum(factorint(n).values()) == 2
def a(n):
return sum(1 for p in mp(str(n)) if p[0]!="0" and c(t:=int("".join(p))))
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CROSSREFS
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KEYWORD
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base,easy,less,nonn
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AUTHOR
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STATUS
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approved
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