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A129998
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Let p < q be consecutive primes. Then p is in the sequence if p+q+p*q is a composite number and if there is a prime number r such that p+q+r is a divisor of p+q+p*q.
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0
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31, 37, 61, 67, 71, 97, 103, 107, 127, 139, 149, 157, 179, 191, 193, 197, 199, 227, 239, 263, 269, 271, 277, 281, 293, 313, 337, 353, 359, 367, 379, 397, 401, 433, 461, 463, 487, 491, 499, 541, 563, 571, 599, 601, 607, 619, 631, 653, 661, 719, 733, 751, 757
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OFFSET
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1,1
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COMMENTS
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31 is a prime number; 31+37+31*37 = 1215 = 3^5*5 is composite. The prime number 13 yields, when added to 31+37, the divisor 81. Therefore 31 is in the sequence.
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LINKS
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MATHEMATICA
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a = {}; For[n = 1, n < 200, n++, b = Prime[n] + Prime[n + 1] + Prime[n]*Prime[n + 1]; If[ ! PrimeQ[b], For[i = 1, Prime[i] < Prime[n]*Prime[n + 1], i++, If[Mod[ b, Prime[i] + Prime[n] + Prime[n + 1]] == 0, AppendTo[a, Prime[n]]]]]]; Union[a, a]
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CROSSREFS
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KEYWORD
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nonn,less
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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