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A129534
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Triangle read by rows: T(n,k) = number of permutations p of 1,...,n, with min(|p(i)-p(i-1)|, i=2..n) = k (n>=2, k>=1).
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4
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2, 6, 22, 2, 106, 14, 630, 88, 2, 4394, 614, 32, 35078, 4874, 366, 2, 315258, 43638, 3912, 72, 3149494, 435002, 42808, 1494, 2, 34620010, 4775184, 496222, 25224, 160, 415222566, 57214716, 6164470, 393792, 6054, 2, 5395737242, 742861262, 82190752, 6070408, 160784, 352
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OFFSET
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2,1
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COMMENTS
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Row n has floor(n/2) terms. Row sums are the factorial numbers (A000142). T(n,1) = A129535(n). Sum(T(n,k), k>=2) = A002464(n). If, in the definition, min is replaced by max, then one obtains A064482.
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REFERENCES
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R. P. Stanley, Enumerative Combinatorics, Cambridge, Vol. 2, 1999; see Problem 6.40.
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LINKS
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EXAMPLE
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T(4,2) = 2 because we have 3142 and 2413.
Triangle starts:
2;
6;
22, 2;
106, 14;
630, 88, 2;
4394, 614, 32;
...
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MAPLE
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k:=3: with(combinat): a:=proc(n) local P, ct, i: P:=permute(n): ct:=0: for i from 1 to n! do if min(seq(abs(P[i][j]-P[i][j-1]), j=2..n))=k then ct:=ct+1 else ct:=ct: fi: od: ct: end: seq(a(n), n=2..8); # yields the first 7 entries in any specified column k
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PROG
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(C++) #include <iostream> #include <vector> #include <algorithm> using namespace std; inline int k(const vector<int> & s) { const int n = s.size() ; int kmin = n+1 ; for(int i=1; i<n; i++) { const int thisdiff = abs(s[i]-s[i-1]) ; if ( thisdiff < kmin) kmin = thisdiff ; } return kmin ; } int main(int argc, char *argv[]) { for(int n=2 ;; n++) { vector<int> s; for(int i=1; i<=n; i++) s.push_back(i) ; vector<unsigned long long > resul(n); do { resul[k(s)]++ ; } while( next_permutation(s.begin(), s.end()) ) ; for(int i=1; i<=n/2; i++) cout << resul[i] << ", " ; cout << endl ; } return 0 ; } - R. J. Mathar, Oct 11 2007
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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