login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A124720
Number of ternary Lyndon words of length n with exactly two 1's.
6
2, 5, 16, 38, 96, 220, 512, 1144, 2560, 5616, 12288, 26592, 57344, 122816, 262144, 556928, 1179648, 2490112, 5242880, 11009536, 23068672, 48233472, 100663296, 209713152, 436207616, 905965568, 1879048192, 3892305920, 8053063680, 16642981888, 34359738368
OFFSET
3,1
COMMENTS
If the offsets are modified, A124720 to A124723 are the 2nd to 5th Witt transform of A000079 [Moree]. - R. J. Mathar, Nov 08 2008
a(n+2) is the number of distinct unordered pairs of binary words having a total length of n letters: a(2+2) = 5 because we have the unordered pairs: (e,00),(e,01), (e,10), (e,11), (0,1) where e represents the empty word. Each pair has a total of 2 letters and the two elements of each pair are distinct words. - Geoffrey Critzer, Feb 28 2013
LINKS
Pieter Moree, The formal series Witt transform, Discr. Math. no. 295 vol. 1-3 (2005) 143-160. [From R. J. Mathar, Nov 08 2008]
FORMULA
G.f.: x^3*(2-3 x)/((1-2 x^2)(1- 2x)^2) = (x^2/(1-2x)^2 - x^2/(1-2*x^2))/2.
From Colin Barker, Oct 28 2016: (Start)
a(n) = 2^(n-3)*(n-1)-2^(n/2-2) for n even.
a(n) = 2^(n-3)*n-2^(n-3) for n odd.
a(n) = 4*a(n-1)-2*a(n-2)-8*a(n-3)+8*a(n-4) for n>6.
(End)
EXAMPLE
a(4) = 5 because 1122, 1123, 1132, 1213, 1133 are all Lyndon words on 3 letters with 2 ones.
MATHEMATICA
nn=30; Drop[CoefficientList[Series[(1/(1-2x)^2-1/(1-2x^2))/2, {x, 0, nn}], x], 1] (* Geoffrey Critzer, Feb 28 2013 *)
PROG
(PARI) Vec(x^3*(2-3*x)/((1-2*x)^2*(1-2*x^2)) + O(x^40)) \\ Colin Barker, Oct 28 2016
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Mike Zabrocki, Nov 05 2006
STATUS
approved