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A122761 Triangular read by rows: T(n, k) = 3^k * (1 + (n mod 2)). 1
1, 2, 6, 1, 3, 9, 2, 6, 18, 54, 1, 3, 9, 27, 81, 2, 6, 18, 54, 162, 486, 1, 3, 9, 27, 81, 243, 729, 2, 6, 18, 54, 162, 486, 1458, 4374, 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 2, 6, 18, 54, 162, 486, 1458, 4374, 13122, 39366, 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,2
REFERENCES
Lynn Arthur Steen and J. Arthur Seebach, Jr., Counterexamples in Topology, Dover, New York, 1978, pp. 57-58.
LINKS
FORMULA
T(n, k) = 3^k * (1 + (n mod 2)).
From G. C. Greubel, Dec 30 2022: (Start)
T(n, k) = 3^k*(3 - (-1)^n)/2.
T(n, 0) = (3 - (-1)^n)/2.
T(n, n) = 3^n*(3 - (-1)^n)/2.
T(2*n, n) = A000244(n).
T(2*n+1, n+1) = 6*T(2*n, n).
T(2*n+1, n) = 2*T(2*n, n).
T(2*n+1, n-1) = 6*T(2*n, n).
Sum_{k=0..n} T(n, k) = (1/4)*(3 - (-1)^n)*(3^(n+1) - 1).
Sum_{k=0..n} (-1)^k*T(n, k) = (1/8)*(3 - (-1)^n)*(1 + (-1)^n*3^(n+1)).
Sum_{k=0..floor(n/2)} T(n-k, k) = (1/8)*(3*(6 - (-1)^binomial(n+1, 2))*3^floor(n/2) - (6 + (-1)^n)). (End)
EXAMPLE
Triangle begins as:
1;
2, 6;
1, 3, 9;
2, 6, 18, 54;
1, 3, 9, 27, 81;
2, 6, 18, 54, 162, 486;
1, 3, 9, 27, 81, 243, 729;
MATHEMATICA
Table[3^k*(1+Mod[n, 2]), {n, 0, 10}, {k, 0, n}]//Flatten
PROG
(Magma) [3^k*(3-(-1)^n)/2: k in [0..n], n in [0..12]]; // G. C. Greubel, Dec 30 2022
(SageMath)
def A122761(n, k): return 3^k*(3-(-1)^n)/2
flatten([[A122761(n, k) for k in range(n+1)] for n in range(13)]) # G. C. Greubel, Dec 30 2022
CROSSREFS
Cf. A000244.
Sequence in context: A121601 A369346 A355929 * A100469 A360857 A124320
KEYWORD
nonn,tabl,easy
AUTHOR
Roger L. Bagula, Sep 21 2006
EXTENSIONS
Name and formula corrected by Jon Perry, Oct 15 2012
Edited by G. C. Greubel, Dec 30 2022
STATUS
approved

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Last modified April 24 22:17 EDT 2024. Contains 371964 sequences. (Running on oeis4.)