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A120355
a(n) = min{k>0: the n-th convergent to e equals m/k! for some m}.
1
1, 1, 3, 4, 7, 8, 13, 71, 31, 67, 13, 89, 83, 18089, 5441, 17377, 36269, 26021, 4909, 10391023, 1097, 28879, 1846921, 519691, 1329313, 793279, 7553783, 3308341, 65676881, 662407, 677311, 2425388512913, 4403182913, 10832561, 781379079653017, 9120403, 2718061
OFFSET
0,3
COMMENTS
Conjecture: for n>5, a(n) = A006530(A007677(n)). - Chai Wah Wu, Feb 25 2026
LINKS
Jonathan Sondow, A geometric proof that e is irrational and a new measure of its irrationality, arXiv:0704.1282 [math.HO], 2007-2010.
Jonathan Sondow, A geometric proof that e is irrational and a new measure of its irrationality, Amer. Math. Monthly 113 (2006) 637-641.
Jonathan Sondow and Kyle Schalm, Which partial sums of the Taylor series for e are convergents to e? (and a link to the primes 2, 5, 13, 37, 463), II, Gems in Experimental Mathematics (T. Amdeberhan, L. A. Medina, and V. H. Moll, eds.), Contemporary Mathematics, vol. 517, Amer. Math. Soc., Providence, RI, 2010.
FORMULA
a(n) = A002034(A007677(n)).
EXAMPLE
The 6th convergent to e is 87/32 and 32 divides 8! but not 7!, so a(6) = 8.
CROSSREFS
KEYWORD
hard,nonn
AUTHOR
Jonathan Sondow, Aug 16 2006
EXTENSIONS
Extended by Max Alekseyev, Jul 28 2009
Missing a(7)=71 inserted by Georg Fischer, Oct 15 2024
a(34)-a(36) from Chai Wah Wu, Feb 25 2026
STATUS
approved