

A119632


Lengths of successive runs in A160357, where a run here means a string of alternating terms.


9



1, 1, 3, 1, 11, 1, 4, 10, 1, 4, 28, 1, 10, 24, 1, 8, 1, 2, 1, 1, 4, 1, 9, 4, 1, 2, 36, 1, 12, 4, 1, 2, 1, 3, 28, 1, 10, 52, 1, 18, 1, 32, 1, 12, 15, 38, 1, 14, 32, 1, 12, 1, 44, 1, 16, 1, 148, 1, 50, 7, 22, 1, 8, 3, 4, 1, 2, 70, 1, 24, 1, 114, 1, 42, 1, 200, 1, 68, 6, 1, 2, 13
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OFFSET

1,3


COMMENTS

Gives a highly compressed version of A005132.
The encoding of Recamán's sequence a(n) = A005132 using A119632 is easy  A119632 counts runs of alternating i(n)'s, where i(n) = (a(n)a(n1)/n = A160357(n).
Note that i(n) is always +1 or 1. Each run ends when i(n) = i(n+1).
Here is pseudocode to reconstruct Recamán's sequence from A119632, which we will call I(n):
a(0) = 0
n = 1
i = 1
for k = 1..
for j = 1..I(k) {
a(n) = a(n1) + n*i
n = n+1
i = i
}
i = i
}
The gzipped file attached to A119632 represents the first 1470117206801829 terms of A005132. The longest run of alternating i(n)'s (maximal value found so far in A119632) is 232144588914. There are 64094657 runs encoded in the gzipped file.


LINKS

Allan Wilks, Table of n, a(n) for n = 1..100000
Allan Wilks, The first 64094657 terms (gzipped). (A large file. This encodes the first 1470117206801829 terms of A005132!)
Index entries for sequences related to Recamán's sequence


EXAMPLE

A160357 begins 1, 1; 1; 1, 1, 1; 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1; 1; 1, 1, 1, 1; 1, 1, 1, 1, 1, 1, 1, 1, 1, 1; 1; ..., where semicolons demark the successive runs.


CROSSREFS

Cf. A005132, A160357.
Sequence in context: A048953 A200652 A276391 * A201131 A277790 A134761
Adjacent sequences: A119629 A119630 A119631 * A119633 A119634 A119635


KEYWORD

nonn


AUTHOR

N. J. A. Sloane and Allan Wilks, Jun 10 2006


EXTENSIONS

Entry expanded by N. J. A. Sloane, Jul 15 2011.
I am having trouble uploading the gzipped file.


STATUS

approved



