OFFSET
1,3
COMMENTS
Gives a highly compressed version of A005132.
The encoding of Recamán's sequence a(n) = A005132 using A119632 is easy - A119632 counts runs of alternating i(n)'s, where i(n) = (a(n)-a(n-1)/n = A160357(n).
Note that i(n) is always +1 or -1. Each run ends when i(n) = i(n+1).
Here is pseudo-code to reconstruct Recamán's sequence from A119632, which we will call I(n):
a(0) = 0
n = 1
i = 1
for k = 1..
for j = 1..I(k) {
a(n) = a(n-1) + n*i
n = n+1
i = -i
}
i = -i
}
LINKS
Allan Wilks, Table of n, a(n) for n = 1..100000
Allan Wilks, The first 64094657 terms (gzipped). (A large file. This encodes the first 1470117206801829 terms of A005132!)
EXAMPLE
A160357 begins 1, 1; 1; -1, 1, 1; 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, 1; 1; -1, 1, -1, -1; 1, -1, 1, -1, 1, -1, 1, -1, 1, 1; 1; ..., where semicolons demark the successive runs.
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane and Allan Wilks, Jun 10 2006
EXTENSIONS
Entry expanded by N. J. A. Sloane, Jul 15 2011.
I am having trouble uploading the gzipped file.
STATUS
approved