OFFSET
1,1
COMMENTS
Numbers k such that, if k+6 has d digits, k*(10^d+1) is the product of two numbers that differ by 7. - Robert Israel, Nov 24 2025
LINKS
Robert Israel, Table of n, a(n) for n = 1..10000
MAPLE
N:= 12: # For terms k where k+6 has <= N digits
f:= proc(d) local x, C;
C:= map(t -> subs(t, x), [msolve((x+6)*(x-1)=0, 10^d+1)]);
C:= map(x -> (x+6)*(x-1)/(10^d+1), C);
op(sort(select(x -> (x+6 >= 10^(d-1) and x + 6 < 10^d), C)))
end proc:
map(f, [$2..N]); # Robert Israel, Nov 24 2025
CROSSREFS
KEYWORD
AUTHOR
Giovanni Resta, Feb 06 2006
STATUS
approved
