OFFSET
1,1
COMMENTS
Also numbers k such that k concatenated with k+9 gives the product of two numbers which differ by 3. For proof that this is the same sequence compare A116133.
Also numbers k such that k concatenated with k-9 gives the product of two numbers which differ by 9.
If k+5 has d digits, the concatenation is k//k+5 = 10^d*k+k+5 = m*(m+5), therefore k//k-1 = 10^d*k+k-1 = (m-1)*(m+6), so there is a large overlap with A116152. - R. J. Mathar, May 22 2026
EXAMPLE
7770160145//7770160136 = 8814851183 * 8814851192, where // denotes concatenation.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Giovanni Resta, Feb 06 2006
EXTENSIONS
Edited by N. J. A. Sloane, Apr 12 2007
STATUS
approved
