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A115024
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Natural numbers n such that the number of prime factors of n (counted with multiplicity) is equal to the number of decimal digits of n.
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4
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2, 3, 5, 7, 10, 14, 15, 21, 22, 25, 26, 33, 34, 35, 38, 39, 46, 49, 51, 55, 57, 58, 62, 65, 69, 74, 77, 82, 85, 86, 87, 91, 93, 94, 95, 102, 105, 110, 114, 116, 117, 124, 125, 130, 138, 147, 148, 153, 154, 164, 165, 170, 171, 172, 174, 175, 182, 186, 188, 190, 195
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OFFSET
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1,1
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LINKS
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EXAMPLE
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25 = 5*5 and 25 has two digits.
116 = 2*2*29 and 116 has three digits.
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MATHEMATICA
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Select[Range[2, 300], Sum[FactorInteger[ # ][[i]][[2]], {i, 1, Length[FactorInteger[ # ]]}] == Floor[Log[10, # ] + 1] &] (* Stefan Steinerberger, Feb 27 2006 *)
Select[Range[200], PrimeOmega[#]==IntegerLength[#]&] (* Harvey P. Dale, Jul 28 2020 *)
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PROG
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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