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A111213
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Difference between the closest squares surrounding prime p is prime.
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1
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3, 3, 5, 5, 7, 7, 11, 11, 13, 13, 13, 13, 17, 17, 17, 17, 19, 19, 19, 23, 23, 23, 23, 29, 29, 29, 29, 31, 31, 31, 31, 31, 31, 37, 37, 37, 37, 37, 37, 41, 41, 41, 41, 41, 41, 41, 43, 43, 43, 43, 43, 43, 43, 47, 47, 47, 47, 47, 47
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OFFSET
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2,1
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COMMENTS
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Conjecture: The number of terms in this sequence is infinite.
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LINKS
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FORMULA
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Let p be a prime number and r = floor(sqrt(p)). Then the closest surrounding squares of p are r^2 and (r+1)^2. So d = (r+1)^2 - r^2 = 2r+1. If d is prime then list d.
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EXAMPLE
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29 is a prime number. 5^2 and 6^2 are the closest squares surrounding 29. Now the difference, 36-25 = 11 is prime so 11 is in the table.
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MAPLE
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g:= proc(q) local x; x:= (q-1)/2; numtheory:-pi((x+1)^2) - numtheory:-pi(x^2) end proc:
seq(p$g(p), p = select(isprime, [seq(i, i=3..1000, 2)])); # Robert Israel, Jun 08 2016
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MATHEMATICA
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Select[Table[Ceiling[#]^2 - Floor[#]^2 &@ Sqrt@ Prime@ n, {n, 120}], PrimeQ] (* Michael De Vlieger, Jun 10 2016 *)
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PROG
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(PARI) surrsqpr(n) = { local(x, y, j, r, d); forprime(x=2, n, r=floor(sqrt(x)); d=r+r+1; if(isprime(d), print1(d", ") ) ) }
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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