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A110236
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Number of (1,0) steps in all peakless Motzkin paths of length n (can be easily translated into RNA secondary structure terminology).
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11
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1, 2, 4, 10, 24, 58, 143, 354, 881, 2204, 5534, 13940, 35213, 89162, 226238, 575114, 1464382, 3734150, 9534594, 24374230, 62377881, 159793932, 409717004, 1051405260, 2700168229, 6939388478, 17845927498, 45922416814, 118238842174
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OFFSET
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1,2
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COMMENTS
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Number of UHD's in all peakless Motzkin paths of length n+2; here U=(1,1), H=(1,0), and D=(1,-1). Example: a(2)=2 because in HHHH, HUHD, UHDH, and UHHD we have a total of 0+1+1+0 UHD's.
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LINKS
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FORMULA
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a(n) = Sum_{k=1..n} k*T(n, k), where T(n, k) = floor(2/(n+k))*binomial((n+k)/2, k)*binomial((n+k)/2, k-1) for n+k mod 2 = 0 and T(n, k)=0 otherwise.
G.f.: (1-z+z^2-Q)/(2*z*Q), where Q = sqrt(1 - 2z - z^2 - 2z^3 + z^4).
a(n) = Sum_{k=1..n} k*A110235(n,k).
a(n) = Sum_{k>=0} k*A190172(n+2,k).
a(n+1) = Sum_{k=0..n} Sum_{j=0..n-k} C(k+j,n-k-j)*C(k,n-k-j). - Paul Barry, Oct 24 2006, index corrected Jul 13 2011
a(n+1) = Sum_{k=0..floor(n/2)} C(n-k+1,k+1)*C(n-k,k); a(n+1) := Sum_{k=0..n} C(k+1,n-k+1)*C(k,n-k). - Paul Barry, Aug 17 2009, indices corrected Jul 13 2011
G.f.: z*S^2/(1-z^2*S^2), where S = 1 + z*S + z^2*S*(S-1) (the g.f. of the RNA secondary structure numbers; A004148).
a(n) = -f_{n}(-n) with f_1(n)=n and f_{p}(n) = (n+p-1)*(n+p+1-1)^2 *(n+p+2-1)^2*...*(n+p+(p-1)-1)^2/(p!*(p-1)!) + f_{p-1}(n) for p > 1. - Alzhekeyev Ascar M, Jun 27 2011
Let A=floor(n/2), R=n-1, B=A-R/2+1, C=A+1, D=A-R and Z=1 if n mod 2 = 1, otherwise Z = n*(n+2)/4. Then a(n) = Z*Hypergeometric([1,C,C+1,D,D-1],[B,B,B-1/2,B-1/2],1/16). - Peter Luschny, Jan 14 2012
D-finite with recurrence (n+1)*a(n) -3*n*a(n-1) +2*(n-3)*a(n-2) +3*(-n+2)*a(n-3) +2*(n-1)*a(n-4) +3*(-n+4)*a(n-5) +(n-5)*a(n-6)=0. - R. J. Mathar, Nov 30 2012
G.f.: ((1-x+x^2)*((x^2+x+1)*(x^2-3*x+1))^(-1/2)-1)/(2*x). - Mark van Hoeij, Mar 27 2013
Recurrence: (n-2)*(n-1)*(n+1)*a(n) = (n-2)*n*(2*n-1)*a(n-1) + (n-1)*(n^2 - 2*n - 2)*a(n-2) + (n-2)*n*(2*n-3)*a(n-3) - (n-3)*(n-1)*n*a(n-4).
a(n) ~ (sqrt(5)+3)^(n+1) / (5^(1/4) * sqrt(Pi*n) * 2^(n+2)). (End)
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EXAMPLE
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a(3)=4 because in the 2 (=A004148(3)) peakless Motzkin paths of length 3, namely HHH and UHD (where U=(1,1), H=(1,0) and D=(1,-1)), we have altogether 4 H steps.
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MAPLE
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T:=proc(n, k) if n+k mod 2 = 0 then 2*binomial((n+k)/2, k)*binomial((n+k)/2, k-1)/(n+k) else 0 fi end:seq(add(k*T(n, k), k=1..n), n=1..33);
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MATHEMATICA
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Rest[CoefficientList[Series[((1-x+x^2)*((x^2+x+1)*(x^2-3*x+1))^(-1/2)-1) /(2*x), {x, 0, 20}], x]] (* Vaclav Kotesovec, Feb 13 2014 *)
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PROG
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(PARI) x='x+O('x^66); Vec(((1-x+x^2)*((x^2+x+1)*(x^2-3*x+1))^(-1/2)-1)/(2*x)) /* Joerg Arndt, Mar 27 2013 */
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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