A109912 Beginning with 1, least multiple of a(n) not divisible by 5 such that no digit is common between a(n) and a(n+1).

1, 2, 4, 8, 16, 32, 64, 128, 3456, 127872, 6649344, 1010700288, 46655946694656, 1313038307827703808, 946546544999554566644656594944, 183011223033027037132010301880878170112

Offset

0,2

Comments

The sequence seems to be finite but not obviously. Can someone prove this and find the last term?

Conjecture: Sequence is infinite with terms from a(12) onwards alternating between integers with the four digits 4,5,6,9 and integers with the remaining six digits 0,1,2,3,7,8. - William Rex Marshall, Jul 19 2005

If a(15) exists then there are 2^18 possible values for a(15) mod 10^18. - David A. Corneth, Sep 11 2025

a(16) <= 35296712898318870569560487*a(15). - Jason Yuen, Sep 14 2025

Links

Table of n, a(n) for n=0..15.

Crossrefs

Cf. A079838, A109913.

Sequence in context: A290851 A290670 A079838 * A079845 A278995 A117302

Adjacent sequences: A109909 A109910 A109911 * A109913 A109914 A109915

Keyword

base,nonn,more

Author

Amarnath Murthy, Jul 16 2005

Extensions

More terms from William Rex Marshall, Jul 19 2005

Status

approved