

A109676


Numbers n such that the sum of the digits of (n!  1) is divisible by n.


0




OFFSET

1,2


COMMENTS

Next term after 42862 (if it exists) is greater than 750,000.


LINKS



EXAMPLE

The digits of 5405!  1 sum to 86480 and 86480 is divisible by 5405, so 5405 is in the sequence.


MATHEMATICA

Do[k = n!  1; s = Plus @@ IntegerDigits[k]; If[Mod[s, n] == 0, Print[n]], {n, 1, 10^5}]


CROSSREFS



KEYWORD

base,hard,more,nonn


AUTHOR



STATUS

approved



