

A108575


Numbers k such that the continued fraction for sqrt(k) is multiplicative.


1



3, 7, 8, 13, 14, 15, 22, 23, 24, 32, 33, 34, 35, 44, 47, 48, 58, 59, 60, 62, 63, 74, 75, 78, 79, 80, 95, 96, 98, 99, 114, 119, 120, 135, 136, 138, 140, 141, 142, 143, 160, 162, 164, 167, 168, 185, 187, 189, 192, 194, 195, 215, 219, 220, 222, 223, 224, 248, 252, 254
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OFFSET

1,1


COMMENTS

m^2  m < a(n) < m^2 for some m.


LINKS



EXAMPLE

The continued fraction for sqrt(7) is c = (2, 1, 1, 1, 4, 1, 1, 1, 4, ...) = A010121. If we index starting at 0, so that c(0) = 2, c is multiplicative (the value at c(0) is immaterial). Hence 7 is in the sequence.


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



