OFFSET
0,4
COMMENTS
Conjecture: number of roots of x^n + 1 in the left half-plane for n > 0. - Michel Lagneau, Oct 31 2012
Maximum bias of polyominoes with n+1 squares. Define the bias of a polyomino to be the difference between the number of black squares and the number of white squares when chessboard coloring is applied to the polyomino. Maximum bias for the value n is defined to be the maximum value of bias among all polyominoes of n squares. - John Mason, Dec 24 2013
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (1,0,0,1,-1).
FORMULA
G.f.: (1-x+x^2+x^3)/(1-x-x^4+x^5)=(1+x^2+2x^3+x^4+2x^5+x^6)/(1-x^4)^2.
a(n) = sum{k=0..n, -mu(k mod 4)}.
a(n) = cos(Pi*n/2)/2-sin(Pi*n/2)/2+(-1)^n/4+(2n+1)/4.
a(n) = sum{k=0..n, Jacobi(2^k, 2k+1)} [Conjecture]. - Paul Barry, Jul 23 2005
a(n) = sum{k=0..n, Product{j=1..k, ((-1)^j)^(k-j+1)}}. - Paul Barry, Nov 09 2007
a(n) = A083219(n-1). - R. J. Mathar, Aug 28 2008
a(n) = numbers of times cos(-Pi/n+2k*Pi/n) < 0 for k = 0..n-1. - Michel Lagneau, Nov 02 2012
a(n) = ((n - 1) mod 4)/2 + (n+1)/2 - 1. - John Mason, Dec 24 2013
a(n) = A018837(n-1) for n > 2. - Georg Fischer, Oct 07 2018
MAPLE
a:= n-> n-1 - 2*floor((n-1)/4):
seq(a(n), n=0..75); # Alois P. Heinz, Jan 24 2021
MATHEMATICA
CoefficientList[Series[(1 - x + x^2 + x^3)/(1 - x - x^4 + x^5), {x, 0, 100}], x] (* Vincenzo Librandi, Dec 31 2013 *)
LinearRecurrence[{1, 0, 0, 1, -1}, {1, 0, 1, 2, 3}, 80] (* Harvey P. Dale, May 07 2018 *)
PROG
(PARI) a(n)=([0, 1, 0, 0, 0; 0, 0, 1, 0, 0; 0, 0, 0, 1, 0; 0, 0, 0, 0, 1; -1, 1, 0, 0, 1]^n*[1; 0; 1; 2; 3])[1, 1] \\ Charles R Greathouse IV, Sep 02 2015
(GAP) List([0..80], n->((n-1) mod 4)/2+(n+1)/2-1); # Muniru A Asiru, Oct 07 2018
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Apr 27 2005
EXTENSIONS
John Mason's contributions corrected for offset by Eric M. Schmidt, Dec 30 2013
STATUS
approved