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A105672
a(1)=1, then bracketing n with powers of 3 as f(t)=3^t for f(t) < n <= f(t+1), a(n) = f(t+1) - a(n-f(t)).
5
1, 2, 1, 8, 7, 8, 1, 2, 1, 26, 25, 26, 19, 20, 19, 26, 25, 26, 1, 2, 1, 8, 7, 8, 1, 2, 1, 80, 79, 80, 73, 74, 73, 80, 79, 80, 55, 56, 55, 62, 61, 62, 55, 56, 55, 80, 79, 80, 73, 74, 73, 80, 79, 80, 1, 2, 1, 8, 7, 8, 1, 2, 1, 26, 25, 26, 19, 20, 19, 26, 25, 26, 1, 2, 1, 8, 7, 8, 1, 2, 1
OFFSET
1,2
FORMULA
a(n+1) = 1 + Sum_{k=1..n} (-1)^k*(2-3*3^valuation(k, 3)).
a(n) = A064235(n) - a(n - A064235(n)/3). - R. J. Mathar, Nov 06 2011
MAPLE
A105672 := proc(n)
option remember;
if n = 1 then
1;
else
fn1 := A064235(n) ;
fn := fn1/3 ;
fn1-procname(n-fn) ;
end if;
end proc:
seq(A105672(n), n=1..80) ; # R. J. Mathar, Nov 06 2011
MATHEMATICA
A064235[n_] := 3^Ceiling[Log[3, n]]; a[1] = 1; a[n_] := a[n] = A064235[n] - a[n - A064235[n]/3]; Table[a[n], {n, 1, 81}] (* Jean-François Alcover, Jul 09 2013, after R. J. Mathar *)
PROG
(PARI) b(n, m)=if(n<2, 1, m*m^logint(n-1, m)-b(n-m^logint(n-1, m), m))
a(n)=b(n, 3)
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, May 03 2005
STATUS
approved