OFFSET
1,3
COMMENTS
If n is in the sequence & m=2^n*(2^(n+1)+2n+1) then sigma(m)+tau(m) =2m because sigma(m)=(2^(n+1)-1)*(2^(n+1)+2n+2), tau(m)=2*(n+1) so sigma(m)+tau(m)=(2^(n+1)-1)*(2^(n+1)+2n+2)+2*(n+1)=2m. Hence 2^A105330*(2^(A105330+1)+2*A105330+1) is a subsequence of A083874. A105331 is this subsequence. Next term is greater than 30500.
No other n < 10^5. -T. D. Noe, Jun 23 2008
No other n < 300000. - T. D. Noe, Apr 03 2009
EXAMPLE
110 is in the sequence because 2^111+2*110+1=2596148429267413814265248164610269 is prime.
MATHEMATICA
Do[If[PrimeQ[2^(m + 1) + 2m + 1], Print[m]], {m, 0, 30500}]
PROG
(PARI) is(n)=isprime(2^(n+1)+2*n+1) \\ Charles R Greathouse IV, Feb 20 2017
CROSSREFS
KEYWORD
more,nonn
AUTHOR
Farideh Firoozbakht, Apr 28 2005
STATUS
approved