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A104232
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Triangle read by rows, based on the morphism f: 1->2, 2->3, 3->{2,1}. First row is 1. If current row is a,b,c,..., then the next row is a,b,c,...,f(a),f(b),f(c),...
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0
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1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 2, 1, 1, 2, 2, 3, 2, 3, 3, 2, 1, 2, 3, 3, 2, 1, 3, 2, 1, 2, 1, 3, 2, 1, 2, 2, 3, 2, 3, 3, 2, 1, 2, 3, 3, 2, 1, 3, 2, 1, 2, 1, 3, 2, 2, 3, 3, 2, 1, 3, 2, 1, 2, 1, 3, 2, 3, 2, 1, 2, 1, 3, 2, 2, 1, 3, 2, 3, 2, 2, 1, 3, 1, 2, 2, 3, 2, 3, 3, 2, 1, 2, 3, 3, 2, 1, 3, 2, 1, 2, 1
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OFFSET
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0,3
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COMMENTS
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This substitution was suggested by looking at the Kenyon border tiling substitutions.
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LINKS
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MATHEMATICA
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s[n_] := n /. {1 -> 2, 2 -> 3, 3 -> {2, 1}}; t[a_] := Join[a, Flatten[s /@ a]]; Flatten[ NestList[t, {1}, 6]]
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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