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A104102
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Number of primes >= p(n)# and < p(n)# + p(n+1)^2 where p(i)=i-th prime, p(i)#=i-th primorial.
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0
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4, 7, 11, 21, 24, 29, 25, 38, 42, 37, 58, 54, 45, 60
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OFFSET
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1,1
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COMMENTS
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Conjecture: a(n) is always > p(n+1)
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LINKS
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EXAMPLE
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p(1)#=2 p(1)#+p(2)^2=11 2 3 5 7 are >=2 and <11 so a(1)=4.
p(2)#=6 p(2)#+p(3)^2=31 7 11 13 17 19 23 29 are >=6 and < 31 so a(2)=7.
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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