A104102 - OEIS

%I #6 Mar 07 2013 11:24:28

%S 4,7,11,21,24,29,25,38,42,37,58,54,45,60

%N Number of primes >= p(n)# and < p(n)# + p(n+1)^2 where p(i)=i-th prime, p(i)#=i-th primorial.

%C Conjecture: a(n) is always > p(n+1)

%e p(1)#=2 p(1)#+p(2)^2=11 2 3 5 7 are >=2 and <11 so a(1)=4.

%e p(2)#=6 p(2)#+p(3)^2=31 7 11 13 17 19 23 29 are >=6 and < 31 so a(2)=7.

%K nonn

%O 1,1

%A _Pierre CAMI_, Mar 04 2005