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A100990
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a(n) = n^21 mod 100.
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2
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0, 1, 52, 3, 4, 25, 56, 7, 8, 9, 0, 11, 12, 13, 64, 75, 16, 17, 68, 19, 0, 21, 72, 23, 24, 25, 76, 27, 28, 29, 0, 31, 32, 33, 84, 75, 36, 37, 88, 39, 0, 41, 92, 43, 44, 25, 96, 47, 48, 49, 0, 51, 52, 53, 4, 75, 56, 57, 8, 59, 0, 61, 12, 63, 64, 25, 16, 67, 68, 69, 0, 71, 72, 73, 24
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OFFSET
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0,3
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COMMENTS
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Also n^(20k+1) mod 100 for any positive integer k.
There are 63 numbers (A075821) where the final two digits of n^21, n^41, n^61, etc. are equal to n.
Period 100.
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LINKS
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FORMULA
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EXAMPLE
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a(11) = 11 since 11^21 = 7400249944258160101211 and the final two digits are 11.
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MATHEMATICA
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PROG
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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