OFFSET
1,1
COMMENTS
FORMULA
a(n) = Numerator[1/n!*Sum[Sum[(i^3+j^3), {i, 1, n}], {j, 1, n}]] a(n) = Numerator[1/2 * (n^3)*(n+1)^2 /n! ].
EXAMPLE
A099903(n)/n! begins 2, 18, 36, 100/3, 75/4, 147/20, 98/45, 18/35, 45/448, ... So a(6) = 147.
MATHEMATICA
Table[ Numerator[ Sum[(i^3 + j^3), {i, n}, {j, n}]/n! ], {n, 60}]
CROSSREFS
KEYWORD
nonn
AUTHOR
Alexander Adamchuk, Oct 29 2004
STATUS
approved