OFFSET
1,2
COMMENTS
Conjecture: a(n) = n!/(p-1)! for all sufficiently large n, where p is the least prime such that n <= 2*p (Amarnath Murthy). A096974 gives numbers n such that a(n) = n!/(nextprime(n/2)-1)! and indicates that this conjecture is most probably false.
EXAMPLE
a(10) = 5040 as 10*9 is not divisible by 8!, 10*9*8 is not divisible by 7! but 10*9*8*7 = 5040 is divisible by 6! = 720.
PROG
(PARI) {for(n=1, 24, p=1; k=0; b=1; while(b&&k<n, p=p*(n-k); d=(n-k)!; if(p%d==0, b=0; print1(p, ", "), k++)))}
CROSSREFS
KEYWORD
nonn
AUTHOR
Amarnath Murthy, Jul 01 2004
EXTENSIONS
Edited and extended by Klaus Brockhaus, Jul 17 2004
STATUS
approved