login
A094765
a(n) = n + 2 * square excess of n.
4
0, 1, 4, 7, 4, 7, 10, 13, 16, 9, 12, 15, 18, 21, 24, 27, 16, 19, 22, 25, 28, 31, 34, 37, 40, 25, 28, 31, 34, 37, 40, 43, 46, 49, 52, 55, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69, 72, 49, 52, 55, 58, 61, 64, 67, 70, 73, 76, 79, 82, 85, 88, 91, 64, 67, 70, 73, 76, 79, 82, 85, 88, 91
OFFSET
0,3
LINKS
S. H. Weintraub, An interesting recursion, Amer. Math. Monthly, 111 (No. 6, 2004), 528-530.
FORMULA
a(n) = n + 2*A053186(n).
G.f.: 3*x/(1-x)^2 - (2/(1-x)) * Sum_{k>=1} (2*k-1)*x^(k^2). The sum is related to Jacobi theta functions. - Robert Israel, Oct 23 2015
MAPLE
seq(3*n - 2*floor(sqrt(n))^2, n=0..1000); # Robert Israel, Oct 23 2015
PROG
(PARI) a(n) = 3*n - 2*sqrtint(n)^2; \\ Michel Marcus, Oct 23 2015
CROSSREFS
KEYWORD
nonn
AUTHOR
N. J. A. Sloane, Jun 10 2004
STATUS
approved