OFFSET
1,1
COMMENTS
From a(2) onwards the n-th power that divides a(n) -1 is 2^n ===> Second term onwards same as A060867 i.e. a(n+1) = (2^n-1)^2.
LINKS
Index entries for linear recurrences with constant coefficients, signature (7,-14,8).
FORMULA
From Colin Barker, Feb 05 2013: (Start)
a(n) = (2^n-2)^2/4 for n>2.
a(n) = 7*a(n-1)-14*a(n-2)+8*a(n-3) for n>5.
G.f.: x*(2*x+1)*(32*x^3-56*x^2+27*x-4) / ((x-1)*(2*x-1)*(4*x-1)). (End)
EXAMPLE
a(6) = 961 and 960 = 64*15.
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Amarnath Murthy, Sep 19 2003
EXTENSIONS
More terms from Ray Chandler, Oct 04 2003
STATUS
approved