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A083921
Start with (1,2) and then concatenate 2^n+1 previous terms, n>=0 and add 2 if a(2^n+1)=1 or add 1 if a(2^n+1)=2.
1
1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1, 1, 2, 1, 2, 1
OFFSET
1,2
EXAMPLE
The first 2^2+1 = 5 terms are 1,2,1,2,1. Concatenate those 5 terms gives 1,2,1,2,1,1,2,1,2,1; the last term a(5) is 1 hence we add 2 and 2^3+1 first terms are 1,2,1,2,1,1,2,1,2,1,2
CROSSREFS
Cf. A083922 (partial sums).
Sequence in context: A006338 A020903 A133083 * A119672 A271608 A087740
KEYWORD
nonn
AUTHOR
Benoit Cloitre, May 09 2003
STATUS
approved