OFFSET
0,2
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..300
FORMULA
a(n) = (n*(2n+3)^n + 1)/(n+1).
a(n) ~ exp(3/2-9/(8*n)) * (2*n)^n. - Amiram Eldar, Feb 05 2026
MATHEMATICA
a[n_] := (n*(2n+3)^n + 1)/(n+1); Array[a, 20, 0] (* Amiram Eldar, Feb 05 2026 *)
PROG
(Magma) [(n*(2*n+3)^n+1)/(n+1): n in [0..20]]; // Vincenzo Librandi, Nov 12 2011
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Apr 23 2003
STATUS
approved
