

A080694


Let u(1)=u(2)=1 and u(k)=abs(u(k1)u(k2)n); sequence gives length of period of u(k).


1



1, 18, 4, 18, 18, 48, 28, 54, 8, 72, 26, 36, 42, 36, 36, 24, 24, 48, 10, 162, 52, 84, 114, 192, 24, 246, 88, 30, 30, 48, 168, 138, 32, 126, 98, 312, 126, 222, 100, 228, 16, 384, 80, 258, 120, 192, 26, 360, 20, 300, 16, 360, 178, 180, 430, 390, 32, 162, 170, 192, 42, 306
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OFFSET

1,2


COMMENTS

u(k) is periodic for any n  see Reble link.


LINKS

Table of n, a(n) for n=1..62.
Don Reble, On the wholeness of Sloane's A080694


EXAMPLE

When n=3, {u(k)} sequence is 1, 1, 3, 1, 5, 1, 7, 3, 7, 1, 9, 5, 7, 1, 9, 5, 7, 1, 9, 5, 7, 1, ... with period (7, 1, 9, 5) of length 4, hence a(3)=4. If n=7 the period of u(k) is (19, 7, 19, 5, 21, 9, 19, 3, 23, 13, 17, 3, 21, 11, 17, 1, 23, 15, 15, 7, 15, 1, 21, 13, 15, 5, 17, 5) of length 28.


CROSSREFS

Sequence in context: A014974 A008575 A059654 * A040314 A160486 A040312
Adjacent sequences: A080691 A080692 A080693 * A080695 A080696 A080697


KEYWORD

nonn


AUTHOR

Benoit Cloitre, Mar 03 2003


EXTENSIONS

Corrected and extended by Vladeta Jovovic, Mar 07 2003
More terms from Don Reble, Mar 08 2003


STATUS

approved



