OFFSET
1,2
COMMENTS
How many such numbers can be formed?
From M. F. Hasler, Jun 22 2007: (Start)
The first (n-1)(n-2)/2 digits of a(n) (part (1) of the formula) remain the same for all subsequent terms.
Terms of the sequence do not really depend on the base: for any base b>n, terms a(1)..a(n) would read the same. Thus one could add "(in base n+1)" to the definition and delete the keyword "base".
The sequence could be extended to terms n>9 in two ways: (1) by writing a(n) according to the prescription in base n+1, but recording the corresponding value in base 10; (2) by providing a convention for encoding digits d > 9, e.g. by pre-pending them with '0#' (knowing they will never occur at the beginning of a(n)), where # is the number of characters used to write the digit (encoded recursively in the same way if #>9). (End)
FORMULA
To get a(n): (1) start with an empty string and always concatenate the smallest possible of the remaining digits, until there are 2n-1 digits left (n "n"s and n-1 other digits); (2) insert the n-1 other digits in-between the "n"s and concatenate this result to the first string. (M. F. Hasler, Jun 22 2007)
EXAMPLE
a(3) = 132323 using 1, 2,2 and 3,3,3 with no two adjacent numbers same.
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Amarnath Murthy, Feb 05 2003
EXTENSIONS
Corrected and extended by M. F. Hasler, Jun 22 2007
STATUS
approved
