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A078466
First cycle is reached under a "Collatz-Fibonacci" transform (cf. comment).
0
1, 3, 7, 8, 11, 13, 14, 18, 24, 26, 27, 29, 32, 33, 36, 37, 39, 40, 43, 45, 46, 51, 52, 56, 57, 61, 62, 63, 65, 66, 85, 86, 87, 94, 100, 101, 103, 105, 106, 107, 109, 111, 113, 114, 115, 121, 130, 131, 136, 141, 142, 145, 146, 147, 153, 155, 158, 164, 166, 167, 168, 169
OFFSET
1,2
COMMENTS
Let x(1)=1 x(2)=n; x(k)=x(k-1)+x(k-2) if x(k-1) and x(k-2) have opposite parities; x(k)=abs(x(k-1)-x(k-2))/2 otherwise. Conjecture : for any n x(k) reaches a cycle among 2 cycles : (1;1;0) and (1;2;3;5). Sequence gives values of n such that (1;1;0) is reached.
FORMULA
a(n)/n seems greater than 2 for n large enough and if limit a(n)/n exists, this limit should be > 2.5. Does a(n)/n = O(log(log(n)))?
CROSSREFS
Sequence in context: A174871 A062863 A194470 * A047528 A069122 A278519
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Jan 02 2003
STATUS
approved