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A077113
Number of nonnegative integer cubes <= n^2.
5
1, 2, 2, 3, 3, 3, 4, 4, 5, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 14, 14, 14, 14, 14, 14, 15, 15, 15, 15, 15, 15, 16, 16, 16, 16, 16, 17, 17, 17, 17, 17, 17, 17, 18, 18, 18, 18, 18, 18, 19
OFFSET
0,2
COMMENTS
a(n) is the least number m such that m^3 > n^2. - Zak Seidov, May 03 2005
LINKS
FORMULA
a(n) = floor(n^(2/3))+1.
a(n) = [x^(n^2)] (1/(1 - x))*Sum_{k>=0} x^(k^3). - Ilya Gutkovskiy, Apr 20 2018
a(n) = A100196(n) + 1. - Amiram Eldar, Apr 05 2025
EXAMPLE
Cubes <= 10^2: 0, 1, 8, 27 and 64, hence a(10) = 5.
MATHEMATICA
Table[Floor[n^(2/3) + 1], {n, 0, 100}] (* Zak Seidov, May 03 2005 *)
PROG
(Python)
from sympy import integer_nthroot
def A077113(n): return integer_nthroot(n**2, 3)[0]+1 # Chai Wah Wu, Aug 15 2025
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Reinhard Zumkeller, Oct 29 2002
EXTENSIONS
Edited by N. J. A. Sloane, Aug 29 2008 at the suggestion of R. J. Mathar
STATUS
approved