OFFSET
1,1
FORMULA
It seems that a(n) = 5*n +O(log(n)) and that a(n)=5*n for infinitely many values of n.
It appears that a(n)=A077468(n+1). - Benoit Cloitre, Jun 04 2004
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, Aug 27 2002
STATUS
approved