login
A072135
Least m such that sqrt(m) has a period 2n continued fraction expansion whose palindrome part concatenates to a palindromic prime.
1
23, 22, 234, 115, 1208, 212, 1269, 999, 7370, 5019, 3087, 244, 2329, 2171, 147112, 90155, 165407, 7939, 57451, 69224, 62064, 19503, 19844, 563298, 265095, 14759823, 121726, 167817, 97100, 808386, 7353035, 1231680, 201722, 4754844, 91904459
OFFSET
2,1
COMMENTS
All terms in the palindromic part of the continued fraction expansion of sqrt(a(n)) are themselves palindromes. - Chai Wah Wu, Sep 15 2021
LINKS
Chai Wah Wu, Table of n, a(n) for n = 2..71 (terms n = 2..49 from Jon E. Schoenfield)
EXAMPLE
23 is in the sequence because it is the first, followed by 47, 96, 98, 119, 128, ... all exhibiting the following property: sqrt(23) = [4; 1, 3, 1, 8], sqrt(47) = [6; 1, 5, 1, 12], sqrt(96) = [9; 1, 3, 1, 18], sqrt(98) = [9; 1, 8, 1, 18], sqrt(119) = [10; 1, 9, 1, 20], sqrt(128) = [11; 3, 5, 3, 22], ... i.e., the continued fraction expansion of their square roots have palindrome parts which concatenate respectively to the 3-digit palprimes 131, 151, 131, 181, 191, 353, ...
CROSSREFS
Sequence in context: A255228 A374669 A255221 * A204633 A010862 A291570
KEYWORD
hard,nice,nonn,base
AUTHOR
Lekraj Beedassy, Jun 26 2002
EXTENSIONS
a(5)-a(36) from Jon E. Schoenfield, Apr 02 2010
STATUS
approved