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A071568
Smallest k>n such that n^3+1 divides k*n^2+1.
10
1, 3, 11, 31, 69, 131, 223, 351, 521, 739, 1011, 1343, 1741, 2211, 2759, 3391, 4113, 4931, 5851, 6879, 8021, 9283, 10671, 12191, 13849, 15651, 17603, 19711, 21981, 24419, 27031, 29823, 32801, 35971, 39339, 42911, 46693, 50691, 54911, 59359
OFFSET
0,2
FORMULA
a(n) = n^3+n+1.
a(n+1) = A101220(n, n+1, 4).
G.f.: (1 - x + 5*x^2 + x^3)/(1 - x)^4. - Philippe Deléham, Jun 06 2015
a(n) = 4*a(n-1)-6*a(n-2)+4*a(n-3)-a(n-4). - Wesley Ivan Hurt, May 04 2021
E.g.f.: exp(x)*(1 + 2*x + 3*x^2 + x^3). - Stefano Spezia, Jul 21 2025
MATHEMATICA
sk[n_]:=Module[{k=n+1, n2=n^2, n3=n^3+1}, While[!Divisible[k*n2+1, n3], k++]; k]; Array[sk, 40] (* Harvey P. Dale, Jun 13 2013 *)
PROG
(PARI) for(n=1, 50, s=n+1; while((s*n^2+1)%(n^3+1)>0, s++); print1(s, ", "))
CROSSREFS
Cf. A101220.
Sequence in context: A277167 A277049 A261148 * A097081 A093406 A393245
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, May 31 2002
EXTENSIONS
a(0) from Philippe Deléham, Jun 06 2015
STATUS
approved