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A071542
Number of steps to reach 0 starting with n and using the iterated process : x -> x - (number of 1's in binary representation of x).
25
0, 1, 2, 2, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7, 7, 7, 8, 8, 9, 9, 10, 10, 10, 10, 11, 11, 11, 11, 12, 12, 12, 12, 13, 13, 14, 14, 15, 15, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 18, 18, 18, 18, 19, 19, 19, 19, 20, 20, 20, 20, 21, 21, 21, 21, 22, 22, 23, 23, 24, 24, 24, 24, 25, 25, 25, 25
OFFSET
0,3
LINKS
FORMULA
a(0)=0, a(n) = 1 + A071542(n - A000120(n)). - Antti Karttunen, Oct 24 2012
It seems that a(n) ~ C n/log(n) asymptotically with C = 1.4... (n = 10^6 gives C = 1.469..., n = 10^7 gives C = 1.4614...).
EXAMPLE
17 (= 10001 in binary) -> 15 (= 1111) -> 11 (= 1011) -> 8 (= 1000) -> 7 (= 111) -> 4 (= 100) -> 3 (= 11) -> 1 -> 0, hence a(17)=8.
MATHEMATICA
Table[-1 + Length@ NestWhileList[# - DigitCount[#, 2, 1] &, n, # > 0 &], {n, 0, 75}] (* Michael De Vlieger, Jul 16 2017 *)
PROG
(PARI) for(n=1, 150, s=n; t=0; while(s!=0, t++; s=s-sum(i=1, length(binary(s)), component(binary(s), i))); if(s==0, print1(t, ", "); ); )
(PARI) a(n)=my(k); while(n, n-=hammingweight(n); k++); k \\ Charles R Greathouse IV, Oct 30 2012
(MIT/GNU Scheme)
;; with memoizing definec-macro:
(definec (A071542 n) (if (zero? n) n (+ 1 (A071542 (- n (A000120 n)))))) ;; Antti Karttunen, Oct 24 2012
CROSSREFS
A179016 gives the unique infinite sequence whose successive terms are related by this iterated process (in reverse order). Also, it seems that for n>=0, a(A213708(n)) = a(A179016(n+1)) = n.
A213709(n) = a((2^(n+1))-1) - a((2^n)-1).
Sequence in context: A274618 A176843 A238263 * A264810 A176841 A176814
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, Jun 02 2002
EXTENSIONS
Starting offset changed to 0 with a(0) prepended as 0 by Antti Karttunen, Oct 24 2012
STATUS
approved