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A069154
Treated as strings, the concatenation c of the prime factors of n, in increasing order, is an initial segment of n. Equivalently, n begins with c.
1
250, 256, 2048, 2176, 2304, 2500, 2560, 2744, 23328, 25000, 25600, 119911, 219488, 236196, 250000, 256000, 262144, 290912, 2097152, 2238728, 2317312, 2359296, 2370816, 2500000, 2560000, 3515625, 3720087, 5117695, 13436683, 21359416, 23592960, 23887872
OFFSET
1,1
COMMENTS
All terms listed above have at most three prime factors. Is there an upper bound to the number of prime factors of terms of this sequence?
Called "enlightened numbers" by J. Pe. Note that the Mathematica program he provides in his web page erroneously recognizes some numbers as members of the sequence, for example 2239488. The smallest member with 4 prime factors is 2377970784 = 2^5*3^5*7^2*79^2. - Giovanni Resta, Apr 01 2013
LINKS
Giovanni Resta, Table of n, a(n) for n = 1..106 (terms < 10^12)
EXAMPLE
The prime factors of 119911 are 11 and 991, which when concatenated yield 11991, an initial segment of 119911. Therefore 119911 is a term of the sequence.
MATHEMATICA
seq = {}; Do[If[PrimeQ[n] || EvenQ[n] && IntegerDigits[n][[1]] != 2, Continue[]]; p = StringPosition[ToString@n, StringJoin[ToString /@ First /@ FactorInteger@n]]; If[p != {} && p[[1, 1]] == 1, Print[n]; AppendTo[seq, n]], {n, 2, 10^6}]; seq (* Giovanni Resta, Apr 01 2013 *)
CROSSREFS
Sequence in context: A371491 A225209 A197363 * A045169 A267856 A268269
KEYWORD
base,nonn
AUTHOR
Joseph L. Pe, Apr 08 2002
EXTENSIONS
Corrected and extended by Giovanni Resta, Apr 01 2013
STATUS
approved