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A065107
Start of the permutation of the primes in the order in which p^2 first appears as a factor of a number in the Fibonacci sequence.
1
2, 3, 5, 7, 13, 11, 17, 19, 29, 23, 37, 47, 41, 61, 31, 89
OFFSET
1,1
COMMENTS
Assuming that there are no square primitive factors in the Fibonacci sequence (an open question), then this sequence continues 53, 43, 113, 73, 109, 233, 59, 107, 199, 67, 97, 71, 101, 149, 79, 139, 83, 151, 281, 421, 211, 137, 103, 157, 307, 521. This is obtained by sorting the pairs (prime(n)*A001602(n), prime(n)) by the first position and noting the order of the primes in the second position. - T. D. Noe, Apr 15 2004
CROSSREFS
Cf. A001602 (smallest m such that prime(n) divides Fibonacci(m)).
Sequence in context: A067836 A332806 A108546 * A338944 A351528 A185956
KEYWORD
nonn,more
AUTHOR
Len Smiley, Nov 21 2001
STATUS
approved